7 thoughts on “Come vote for four extra SOTR releases!” - NO SPOILERS and NO CURSING

    1. Yeah, I even educated myself on notes as well to see the question is wrong. In any case if someone else wanted to answer you can do the conversion minim = 8, crotchet = 4, quaver = 2, semiquaver = 1. To be more precise semiquaver is 1/16 of a note while semiquaver is double that so 2/16 and so on, but the first way which is practically counting 1/16s is easier.

      The question gives us a Minim, 4 Quavers, 3 crotchets, and a semiquaver which = 8 + 4*2 + 3*4 =3 = 29

      For the answer to be an odd number there needs to be an odd number of semiquavers, which should be C but C equals 37.

      For all the possible answers we get A = 34, B = 30, C = 37 and D = 38. You might say that B is the closest one so this has to be the original correct answer, but C was the only answer with the correct amount of semiquavers, and it is also off by a single unit of measurement (if it had one less minim it would be correct) so I have no idea what to choose from the 2.

  1. If you add together a Minim (1/2 note OR 0.5 each), 4 Quavers (1/8 notes OR 0.125 each), 3 crotchets (1/4 notes OR 0.25 each), and a semiquaver (1/16 notes OR 0.0625 each), you will have the same value as…
    0.5 + 0.5 + 0.75 + 0.0625 =
    1.8125 Full Music Notes/Semibreve’s

    WHICH MEANS… NONE are the correct answer.

    A.) 3 Minims (1.5), 3 Quavers (0.375), and 4 semiquavers (0.25) = 2.125
    B.) 1 Minim (0.5), 4 crotchets (1), 2 Quavers (0.25), and 2 semiquavers (0.125) = 1.875 (This is the closest to the right answer though)
    C.) 2 Minims (1), 3 crotchets (0.75), 3 Quavers (0.375), and 3 semiquavers (0.1875) = 2.3125
    D.) 1 Minim (0.5), 2 Quavers (0.25), 6 crotchets (1.5), and 2 semiquavers (0.125) = 2.375

    Please correct me if this is wrong, but I am 99% sure about my math, since math is my strong suit. @etvo. I could really use a response just informing me if I was right in the above (And that you made changes), or if I am completely wrong in my math. Anyone else see this dilemma I am in/find out that there are no right answers?

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